Open
Description
Code
type T = u8;
type A = Fn()->(T)::Y;
type B = Fn()->T::Y;
Current output
warning: unnecessary parentheses around type
--> src/lib.rs:3:16
|
3 | type A = Fn()->(T)::Y;
| ^ ^
|
= note: `#[warn(unused_parens)]` on by default
help: remove these parentheses
|
3 - type A = Fn()->(T)::Y;
3 + type A = Fn()->T::Y;
Desired output
< nothing at all >
Rationale and extra context
The snippet is syntactically valid, and when generating HIR output, it contains no errors whatsoever, only this pesky warning that says to make the first line like the second.
But they are not equivalent, as the HIR output clearly shows:
#[prelude_import]
use ::std::prelude::rust_2015::*;
#[macro_use]
extern crate std;
type T = u8;
type A = <Fn() -> T>::Y;
type B = Fn() -> T::Y;
The errors emitted when trying to generate MIR output further demonstrate that these are very different things, and the parenthesis really do matter:
error[E0223]: ambiguous associated type
--> src/lib.rs:3:10
|
3 | type A = Fn()->(T)::Y;
| ^^^^^^^^^^^^
|
help: if there were a trait named `Example` with associated type `Y` implemented for `(dyn Fn() -> u8 + 'static)`, you could use the fully-qualified path
|
3 - type A = Fn()->(T)::Y;
3 + type A = <(dyn Fn() -> u8 + 'static) as Example>::Y;
|
error[E0223]: ambiguous associated type
--> src/lib.rs:4:16
|
4 | type B = Fn()->T::Y;
| ^^^^
|
help: if there were a trait named `Example` with associated type `Y` implemented for `u8`, you could use the fully-qualified path
|
4 - type B = Fn()->T::Y;
4 + type B = Fn()-><u8 as Example>::Y;
Rust Version
rustc 1.90.0-nightly (b03b3a7ec 2025-06-26)
binary: rustc
commit-hash: b03b3a7ec92682be2917540b679478d41c95a30c
commit-date: 2025-06-26
host: x86_64-unknown-linux-gnu
release: 1.90.0-nightly
LLVM version: 20.1.7