add tkinter.font stub

[Akuli]

fixes python/mypy#9157

[hauntsaninja]

Maybe:

Suggested change

	str, Font, Tuple[str, int], Tuple[str, int, Tuple[str, ...]], Tuple[str, int, List[str]],
	str, Font, Tuple[str, int], Tuple[str, int, Sequence[str]],

[Akuli]

Tkinter does not accept arbitrary sequences. It only works with lists and tuples.

>>> tkinter.Label(font=('Helvetica', 12, collections.deque(['bold'])))
Traceback (most recent call last):
  ...
_tkinter.TclError: unknown font style "deque(['bold'])"

[hauntsaninja]

I think technically these last two overloads should be:

Suggested change

	@overload
	def actual(self, option: None, *, displayof: Optional[tkinter.Misc] = ...) -> _FontDict: ...
	@overload
	def actual(self, *, displayof: Optional[tkinter.Misc] = ...) -> _FontDict: ...
	@overload
	def actual(self, option: None = ..., displayof: Optional[tkinter.Misc] = ...) -> _FontDict: ...

since e.g, you could pass None, None positionally

[Akuli]

How would the type checker know that some_font.actual() is same as passing None for the option? Maybe just remove * from the actual(self, option: None, *, ...) overload?

[hauntsaninja]

Because it'd be the only overload where both parameters have default values.
What you've done also works :-)