The currently used custom scalar types are all strings, as noted in the comments. Using `unknown` instead of `any` would also be the type safe way as described [here](https://www.typescriptlang.org/docs/handbook/release-notes/typescript-3-0.html#new-unknown-top-type).
The currently used custom scalar types are all strings, as noted in the comments.
Using
unknowninstead ofanywould also be the type safe way as described here.