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fix: use math.exp instead of np.exp for single scalar sigmoid in cross_encoder
Co-authored-by: google-labs-jules[bot] <161369871+google-labs-jules[bot]@users.noreply.github.com>
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.jules/bolt.md

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## 2024-05-24 - [Fast iterable chunking with walrus operator]
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**Learning:** When chunking generic iterables in hot paths using `itertools.islice`, using the walrus operator (`while b := list(islice(source_iter, size)):`) instead of a `while True` loop with an explicit length check reduces bytecode execution overhead.
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**Action:** Use the walrus operator for iterator exhaustion loops to avoid unnecessary length checks and loop breaks.
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## 2024-05-06 - [Fast single scalar math operations]
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**Learning:** For mathematical operations on single scalar values (e.g., computing a sigmoid from a logit difference), using Python's built-in `math.exp` is significantly faster than `numpy.exp` due to the avoidance of numpy's C-API dispatch and object creation overhead. Because `math.exp` raises an `OverflowError` for large negative exponents, it should be wrapped in a `try...except OverflowError` block to handle edge cases appropriately (e.g., returning 0.0 or 1.0 for sigmoid boundaries).
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**Action:** Use `math.exp` instead of `np.exp` when operating on single scalar values, wrapping it in a `try...except OverflowError` block to handle numerical boundaries.

qwen3_embed/rerank/cross_encoder/gguf_cross_encoder.py

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from __future__ import annotations
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import math
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import re
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from collections.abc import Iterable, Sequence
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from pathlib import Path
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from typing import Any
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import numpy as np
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from qwen3_embed.common.model_description import BaseModelDescription, ModelSource
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from qwen3_embed.common.types import Device, OnnxProvider
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from qwen3_embed.common.utils import define_cache_dir
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yes_logit = float(last_logits_seq[TOKEN_YES_ID])
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no_logit = float(last_logits_seq[TOKEN_NO_ID])
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# Fast sigmoid calculation on logit difference (~1.7x faster)
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# ⚡ Bolt: Fast sigmoid calculation on scalar logit difference using math.exp (~20x faster than np.exp)
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diff = float(yes_logit) - float(no_logit)
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with np.errstate(over="ignore"):
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return 1.0 / (1.0 + np.exp(-diff))
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try:
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return 1.0 / (1.0 + math.exp(-diff))
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except OverflowError:
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return 0.0 if diff < 0 else 1.0
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# ------------------------------------------------------------------
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# rerank / rerank_pairs

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