Add solution and test-cases for problem 2410

Author: 0xff-dev

leetcode/2401-2500/2410.Maximum-Matching-of-Players-With-Trainers/README.md

@@ -1,28 +1,33 @@
 # [2410.Maximum Matching of Players With Trainers][title]
 
-> [!WARNING|style:flat]
-> This question is temporarily unanswered if you have good ideas. Welcome to [Create Pull Request PR](https://github.com/kylesliu/awesome-golang-algorithm)
-
 ## Description
+You are given a **0-indexed** integer array `players`, where `players[i]` represents the **ability** of the `ith` player. You are also given a **0-indexed** integer array `trainers`, where `trainers[j]` represents the **training capacity** of the `jth` trainer.
+
+The `ith` player can **match** with the `jth` trainer if the player's ability is **less than or equal** to the trainer's training capacity. Additionally, the `ith` player can be matched with at most one trainer, and the `jth` trainer can be matched with at most one player.
+
+Return the **maximum** number of matchings between `players` and `trainers` that satisfy these conditions.
 
 **Example 1:**
 
 ```
-Input: a = "11", b = "1"
-Output: "100"
+Input: players = [4,7,9], trainers = [8,2,5,8]
+Output: 2
+Explanation:
+One of the ways we can form two matchings is as follows:
+- players[0] can be matched with trainers[0] since 4 <= 8.
+- players[1] can be matched with trainers[3] since 7 <= 8.
+It can be proven that 2 is the maximum number of matchings that can be formed.
 ```
 
-## 题意
-> ...
+**Example 2:**
 
-## 题解
-
-### 思路1
-> ...
-Maximum Matching of Players With Trainers
-```go
 ```
-
+Input: players = [1,1,1], trainers = [10]
+Output: 1
+Explanation:
+The trainer can be matched with any of the 3 players.
+Each player can only be matched with one trainer, so the maximum answer is 1.
+```
 
 ## 结语
 

leetcode/2401-2500/2410.Maximum-Matching-of-Players-With-Trainers/Solution.go

@@ -1,5 +1,19 @@
 package Solution
 
-func Solution(x bool) bool {
-	return x
+import "sort"
+
+func Solution(players []int, trainers []int) int {
+	sort.Ints(players)
+	sort.Ints(trainers)
+	i, j := 0, 0
+	ans := 0
+	for i < len(players) && j < len(trainers) {
+		if trainers[j] >= players[i] {
+			i, j = i+1, j+1
+			ans++
+			continue
+		}
+		j++
+	}
+	return ans
 }

leetcode/2401-2500/2410.Maximum-Matching-of-Players-With-Trainers/Solution_test.go

@@ -9,31 +9,30 @@ import (
 func TestSolution(t *testing.T) {
 	//	测试用例
 	cases := []struct {
-		name   string
-		inputs bool
-		expect bool
+		name              string
+		players, trainers []int
+		expect            int
 	}{
-		{"TestCase", true, true},
-		{"TestCase", true, true},
-		{"TestCase", false, false},
+		{"TestCase1", []int{4, 7, 9}, []int{8, 2, 5, 8}, 2},
+		{"TestCase2", []int{1, 1, 1}, []int{10}, 1},
 	}
 
 	//	开始测试
 	for i, c := range cases {
 		t.Run(c.name+" "+strconv.Itoa(i), func(t *testing.T) {
-			got := Solution(c.inputs)
+			got := Solution(c.players, c.trainers)
 			if !reflect.DeepEqual(got, c.expect) {
-				t.Fatalf("expected: %v, but got: %v, with inputs: %v",
-					c.expect, got, c.inputs)
+				t.Fatalf("expected: %v, but got: %v, with inputs: %v %v",
+					c.expect, got, c.players, c.trainers)
 			}
 		})
 	}
 }
 
-//	压力测试
+// 压力测试
 func BenchmarkSolution(b *testing.B) {
 }
 
-//	使用案列
+// 使用案列
 func ExampleSolution() {
 }